求助一个数学问题

2024-12-29 11:10:17
推荐回答(1个)
回答1:

log3(27m^2)=log3(27)+log3(m^2)=3+2log3(m)
f(x)=((log3(m))^2-2log3(m)-3)x^2-(log3(m)-3)x
由题意
((log3(m))^2-2log3(m)-3)x^2-(log3(m)-3)x-1<0
左边是个二次函数,如果要使其值恒为负,需a<0,判别式<0
(log3(m))^2-2log3(m)-3<0
(log3(m)-3)^2+4(log3(m))^2-8log3(m)-12<0
log3(m)有意义必须m>0
解不等式就得到。
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