(x+1)(x+3)-(x-2)平方是多少

要过程
2025-02-23 05:51:11
推荐回答(4个)
回答1:

(x+1)(x+3)-(x-2)²
=x²+4x+3-(x²-4x+4)
=x²+4x+3-x²+4x-4
=8x-1

回答2:

(x+1)(x+3)-(x-2)平方
=x^2+4x+3-x^2+4x-4
=8x-1

回答3:

x^4+6*x^3+19*x^2+30*x+25

回答4:

8x-1