∫(0→π)(x* sin x)^2的定积分

2025-03-10 11:13:19
推荐回答(1个)
回答1:

=1/2∫x²(1-cos2x)dx
=x³/6-1/4∫x²dsin2x
=π³/6-x²sin2x/4+1/4∫sin2xdx²
=π³/6-1/4∫xdcos2x
=π³/6-xcos2x/4+sin2x/8
=π³/6-π/4