上面说消去y就得到下面那个式子,怎么消y?能把具体过程告诉我吗

2025-03-07 03:51:06
推荐回答(1个)
回答1:

3x+y-6=0 y=6-3x

x²+y²-2y-4
=x²+y²-2y+1-5
=x²+(y²-2y+1)-5
=x²+(y-1)²-5
=x²+(6-3x-1)²-5
=x²+(5-3x)²-5
=x²+25-30x+9x²-5
=10x²-30x+20
=10(x²-3x+2)
10(x²-3x+2)=0
x²-3x+2=0