两道比例数学应用题,各位数学高手进来帮我解决一下!

2024-12-22 20:44:54
推荐回答(6个)
回答1:

1.甲:乙=3:5,甲、乙两数的差是8,甲数和乙数分别是多少?(列出方程和算术法两种方法)

解答:假设甲为x,乙为y.
依题意得:
x:y=3:5 (1)
y-x=8 (2)
(1)式可化为x=3y/5 (3)
(3)式代入(2)式得
y-3y/5=8
解得y=20
代入(3)式,得x=12
答:甲数和乙数分别是12,20.
5-3=2
8÷2=4
3×4=12(甲) 5×4=20(乙)

2.A与B成反比例,B与C成反比例,A与C成什么比例?(请说出理由)
解答:AB=k1(一定),BC=k2(一定)
(AB)/(BC)=A/C=k1/k2(一定)
A与C成正比例

回答2:

5-3=2
8÷2=4
3×4=12(甲) 5×4=20(乙)
解:设每一份为x,则甲为3x,乙为5x
5x-3x=8
x=4
甲:4×3=12,乙:4×5=20

AB=k1(一定),BC=k2(一定)
(AB)/(BC)=A/C=k1/k2(一定)
A与C成正比例

回答3:

1. 甲数和乙数分别是x,y
x/y=3/5
y-x=8
x=12
y=20
(8/2)*3=12
(8/2)*5=20
2. B=K/A
B=T/C
C=(T/K)A
A与C成正比例

回答4:

1、方程法:设甲=3X,乙=5X,则甲与乙的差为2X,即:
5X-2X=8, 则X=4,所以甲=3X=3*4=12,乙=5X=5*4=20;
算术法:甲:乙=3:5,把甲看成3份,乙看成5份,差为2份=8,则每份=4,甲=4*3=12,乙=4*5=20。算术如下:
8÷(5-3)=4
4*3=12
4*5=20

2、A与C成正比例。理由如下:
因A与B成反比例,设A*B=m(m为常数)......................................(式1);
因B与C成反比例,设B*C=n(n为常数)........................................(式2);
式1除以式2,得A/C=m/n
因m/n为常数,故A与C成反比例。

回答5:

5-3=2
8÷2=4
所以3(甲)×4=12 (乙)5×4=20
设每一份为x,则甲为3x,乙为5x
5x-3x=8
x=4
甲:4×3=12,乙:4×5=20

AB=k1(一定),BC=k2(一定)
(AB)/(BC)=A/C=k1/k2(一定)

回答6:

1.设甲=3x,乙=5x。依题意得
5x-3x=8
解得x=4
则甲=12,乙=20
2.A与C成正比

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