等比数列{an}中,s4=1,s8=4,则s12=多少? 要详解答案,我采纳!急用!

2025-02-22 14:01:41
推荐回答(1个)
回答1:

sn=a1(1-q^n)/(1-q)

a1(1-q^4)/(1-q)=1
a1(1-q^8)/(1-q)=4
(1-q^8)/(1-q^4)=4
q^4+1=4
q^4=3
a1(1-3)/(1-q)=1
a1/(1-q)=-1/2

s12=a1(1-q^12)/(1-q)
=a1/(1-q)*[1-(q^4)^3]
=-1/2*(1-27)
=13