一道小学六年级数学题!紧急啊!!今晚必须要!谁快谁拿分啊!

2024-12-15 22:47:11
推荐回答(3个)
回答1:

楼主,你好:
削成最大圆柱体后直径就是正方体边长。根据公式的V=d^3*1/4π,所以面积是原来的4/1π倍,同理另一个也一样,既体积差为240*1/4π=60π 括号2的圆锥为1/3,既60π/3=20π
希望采纳,谢谢!

回答2:

解:设两个正方体的边长分别为a与b
削成最大圆柱时,圆柱的横切底面与正方体的横切底面正方形相内切
∴圆柱的横切底面半径=正方形边长的一半,分别是 a/2 及 b/2
从而 把它们削成最大圆柱后,这两个圆柱的体积之差V1=V大-V小
=π *(a/2)^2*a-π *(b/2)^2*b
=π/4*a^3-π/4*b^3
=π/4*(a^3-b^3)
又 a^3-b^3=240
∴=π/4*(a^3-b^3)=π/4*240=60π

∵圆锥的体积是对应的圆柱体积的三分之一
∴削成最大圆锥,则两个圆锥体积相差V2=1/3V大-1/3V小
=1/3(V大-V小)
=1/3*60π
=20π

回答3:

题目有问题啊“正方体的体积之差是240平方厘米”
如果是立方厘米的话
正方体体积之差a3-b3=240
圆柱体体积之差π(a/2)2*a-π(b/2)2*b=π/4*(a3-b3)=60π
圆锥体体积之差1/3(60π)=20π (圆锥体的体积为相同半径的圆柱体的1/3)
望采纳~~~

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