初一下学期数学题 1.8-8x⼀1.2 - 1.3-3x = 5x-0.4⼀0.3怎么解? 求各位高手帮忙解解,急需急需!谢谢了。!

2024-12-22 00:39:27
推荐回答(4个)
回答1:

(1.8-8x)/1.2 - (1.3-3x)/2 = (5x-0.4)/0.3 (去括号)
=>1.8/1.2-8x/1.2 - 1.3/2 +3x/2=5x/0.3 - 0.4/0.3
=>3/2 -2x/0.3 -1.3/2 +3x/2=5x/0.3 - 4/3 (x项移到一边,其他到等式另一边)
=>5x/0.3+2x/0.3-3x/2=4/3+3/2-1.3/2 (等式两边分母化成相同的)
=>10x/0.6+4x/0.6-(0.9x)/0.6=8/6+9/6-3.9/6
=>(10x+4x-0.9x)/0.6=(8+9-3.9)/6
=>x=(8+9-3.9)/6*0.6/13.1=0.1

回答2:

(1.8-8x)/1.2 - (1.3-3x)/2 = (5x-0.4)/0.3 (去括号)
=>1.8/1.2-8x/1.2 - 1.3/2 +3x/2=5x/0.3 - 0.4/0.3
=>3/2 -2x/0.3 -1.3/2 +3x/2=5x/0.3 - 4/3 (x项移到一边,其他到等式另一边)
=>5x/0.3+2x/0.3-3x/2=4/3+3/2-1.3/2 (等式两边分母化成相同的)
=>10x/0.6+4x/0.6-(0.9x)/0.6=8/6+9/6-3.9/6
=>(10x+4x-0.9x)/0.6=(8+9-3.9)/6
=>x=(8+9-3.9)/6*0.6/13.1=0.1
这完全是一次方程,移项之类的就可以,如果还有不懂的地方,可以来问我,我会尽力为你会打的

回答3:

这个一元六次方程怎么解?这是英国大一学生的一道数学作业。 先求x的而3个中括号内的代数式也都>0,使方程式不可能成立所以-x<1,即x>-

回答4:

变形 (把X前面的系数相加,把不带X的自然数相加,把小数用最简便的分数表述) 得 1/2-(29/3)X=5x-4/3
移项,合并同类项得
11/6=(44/3)X 得知X=(11/6 )/ (44/3)=1/8

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