解方程：x+（2⼀x-1）=a+2⼀( a-1)

x+（2/x-1）=a+2/( a-1)
x-a+2/(x-1)-2/(a-1)=0
x-a+2(a-1-x+1)/[(x-1)(a-1)]=0
x-a-2(x-a)/[(x-1)(a-1)]=0
(x-a){1-2[(x-1)(a-1)]}=0
x-a=0或1-2[(x-1)(a-1)]=0

x-a=0
x=a

1-2[(x-1)(a-1)]=0
2[(x-1)(a-1)]=1
(x-1)(a-1)=2
x-1=2/(a-1)
x=1+2/(a-1)=(a+1)/(a-1)

所以x=a,x=(a+1)/(a-1)

x-a+2/(x-1)-2/(a-1)=0
x-a+2(a-1-x+1)/[(x-1)(a-1)]=0
x-a-2(x-a)/[(x-1)(a-1)]=0
(x-a){1-2[(x-1)(a-1)]}=0
x-a=0或1-2[(x-1)(a-1)]=0

x-a=0
x=a

1-2[(x-1)(a-1)]=0
2[(x-1)(a-1)]=1
(x-1)(a-1)=2
x-1=2/(a-1)
x=1+2/(a-1)=(a+1)/(a-1)

所以x=a,x=(a+1)/(a-1)

2-x=a+2/a-2
4-x-a-2/a=0