几道高二数学题，请大家帮忙解下、给大概过程

1, (k+3)^2-4*9/4=k(k+6)<0 -62, √x>ax+3/2 解为4＜x＜c ,
x=4,x=c是方程 ax-√x+3/2=0的解
4a-2+3/2=0 ，a=1/8,
1/8*c-√c+3/2=0， c=36
3，logb(x-5)<1/a， 0 x-5>b^(1/a) x>5+b^(1/a)
4, sinx - √3*cosx=(4m-6)/(4-m)
sin(x-π/3)=(4m-6)/2(4-m)
-1<=(4m-6)/2(4-m)<=1
-1<=m<=7/3
5, f(x+1)≤f(x)+1
f(x+5)≤f(x+4)+1≤f(x+3)+2≤f(x+2)+3≤f(x+1)+4≤f(x)+5
f(x+5)≥f(x)+5
f(x+5)=f(x)+5
f(2006)=f(2001)+5=f(1996)+2*5=......=f(1)+401*5=2006
g(2006)=f(2006)+1-2006=1.

1.lgx x必须大于0
2