i<<4在C++中是什么意思

2025-03-15 09:10:39
推荐回答(4个)
回答1:

<<在C++中,有两个运算含义:
1.重载输出流运算符,一般运用格式为:cout<2.数据移位运算符,左移几位,如:x=i<<4;就是将i的值左移4位(放大2的4此方)后,赋给x,若i=2,则X=32。

回答2:

将数字i左移4位。

<<是左移运算符的意思,左移运算符是用来将一个数的各二进制位全部左移若干位。例如:

将a的二进制数左移2位,右补0。若a=15,即二进制数00001111,左移2位得00111100,即十进制数60(为简单起见,用8位二进制数表示十进制数15,如果用16位二进制数表示,结果是一样的)。

高位左移后溢出,舍弃。

语法格式:需要移位的数字 << 移位的次数

例如: 3 << 2,则是将数字3左移2位。

扩展资料:

>>右移运算符

运算规则:

按二进制形式把所有的数字向右移动对应的位数,低位移出(舍弃),高位的空位补符号位,即正数补零,负数补1。

语法格式:需要移位的数字 >> 移位的次数

例如:11 >> 2,则是将数字11右移2位

参考资料:百度百科—左移运算符

回答3:

<<是左移运算符,i<<4,是按位左移4位,例如:
i=8;
i<<4位后,,变成:
0000 0000 0000 1000 =8
0000 0000 1000 0000 =128

回答4:

"<<"这个运算符一般做标准的标准流输出运算符,但经过重载后可以做很多用途,如果i重载了,则这句很肯能就是输出4的意思

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