(1+1⼀2)*(1+1⼀3)*(1+1⼀4)*一直到.....*(1+1⼀99)*(1+1⼀100) 这是乘号 * 这是分数1⼀2 因该知道的

数学寒假作业的题 可以用简便方法的 我忘了 帮帮忙 (*^__^*)
2024-12-28 07:20:12
推荐回答(5个)
回答1:

第一个分数可以通分为3/2。第二个是4/3,所以,两个可以约分!
这是固定思路,也是一种做题技巧。

回答2:

晕!这个啊! 你看啊 !

= (n +1) / n (n = 2,3,4.....100 )

=3/2 * 4/3 * 5/4 *....*101/100 (每一项的分子与其后一项的分母约分)

= 101/2

回答3:

每一项进行通分,则
原式=(3/2)*(4/3)*(5/4)*……*(100/99)*(101/100)
=101/2

回答4:

(3/2)*(4/3)*(5/4)*...*(100/99)*(101/100)=101/2
中间的分子分母都可以约掉

回答5:

同学 你仔细看啊 第一个括号里是3/2 第二个是4/3 你懂得

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