急急急!当x趋向于无穷,lim(1-2⼀x)^x-2的极限是多少?

2024-12-17 16:42:04
推荐回答(2个)
回答1:

令1/a=-2/x
x=-2a
所以原式=lim(a→∞)(1+1/a)^(-2a-2)
=lim(a→∞)1/(1+1/a)^(2a+2)
=lim(a→∞)1/[(1+1/a)^a]^2*(1+1/a)^2
=1/e^2

回答2:

lim(x→∞)(1-2/x)^(x-2)

=lim(x→∞)(1-2/x)^x/lim(x→∞)(1-2/x)^(-2)
=lim(x→∞)[(1-2/x)^(-x/2)]^(-2)
=1/e^2