你好，Gloria1o7 (√3+√2)^2003×(√3-√2)^2005=[(√3+√2)(√3-√2)]^2003×(√3-√2)²=(1)^2003×(3+2-2√6)=5-2√6
(√3+√2)^2003 × (√3-√2)^2005 =(√3+√2)^2003 × (√3-√2)^2002 × (√3-√2)^2 =(3-2)^2003 × (3+2-2√6) =5-2√6
