计算:(2+1)(2^2+1)(2^4+1)(2^8+1)等于多少

2024-12-25 03:31:23
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回答1:

解:原式=(2-1)(2+1)(2²+1)(2^4+1)(2^8+1)
=(2²-1)(2²+1)(2^4+1)(2^8+1)
=(2^4-1)(2^4+1)(2^8+1)
=(2^8-1)(2^8+1)
=2^16-1