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51问答网 > AaBb符合自由组合定律，连续自交三代，杂合子所占比例？（求详细过程）

AaBb符合自由组合定律，连续自交三代，杂合子所占比例？（求详细过程）

2025-03-15 07:28:54

推荐回答（1个）

回答1：

这说明你要求的每代中的杂合子，第一次杂合子所占比例是1-1/2×1/2=3/4，第二次杂合子是3/4×3/4=9/16，第三次杂合子是9/16×3/4=27/64。然后以后遇到类似的题你可以把他们拆开算，当然这是在你基础不是很好的情况下用这种方法我个人认为比较好。

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