高等数学:第6题(1)(2)(3)(4)怎么做。需要详细过程。急急

2025-03-10 13:56:50
推荐回答(1个)
回答1:

6(1)
az/ax=4x3-8xy2
a2z/ax2=12x2-8y2
a2z/axay=-16xy
az/ay=4y3-8x2y
a2z/ay2=12y2-8x2
a2z/ayax=-16xy

6(3)
∂z/∂y = xy^(x-1)
∂²z/∂y² = x(x-1)y^(x-2)
∂z/∂x = lny y^x
∂²z/∂x² = ln²y y^x