(1)a交b=2<x<3,c:a>0时,a<x<3a,a>0时,3a<x<a.要使a交b包含于c,则a>0,a<=2,3a>=3.得1<=a<=2. (2)Cia交Cib=-4<=x<=-2,得a<0.3a<-4,a>-2,得-2<a<-4/3