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右下连续不一定可导，为什么还说连续函数一定有原函数

2025-03-15 10:03:54

推荐回答（1个）

回答1：

不要把一个函数(用f(x)表示)和它的原函数(用F(x)表示)混为一谈.
f(x)不一定可导,定义中也没有去计算f'(x).但是它的原函数F(x)却一定可导,并且这个原函数的导数F'(x)(注意不是f'(x))等于f(x),这并不矛盾.

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