(1)
f(x)在1处连续:
lim x->1- f(x)=lim x->1+ f(x)
A=B-1
概率密度函数全局积分=1:
积分<0,1>Axdx+积分<1,2>(B-x)dx=1
A/2+B-3/2=1
A+2B=5
联立可得
B=2
A=1
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(2)
x<=0:F(x)=0
0
1
=(1/2)+2(x-1)-(x^2-1)/2
=2x-x^2/2-1
2
(3)
P{1/2