摩尔质量计算问题

2025-04-02 09:33:45
推荐回答(5个)
回答1:

溶液80ml不能说明质量就是80克,因为水里面溶解了氢氧化钾,所以密度不是1。


具体算法如图,先利用溶质不变,求出溶液质量。

回答2:

首先,80ML不等于80克,因为这是溶液不是纯水,
换一个思路,从14%到28%浓度翻倍,溶质不变,水减少100克,
很简单口算可以得出原本溶液是200克,那么溶质就是14克,水186克
现在溶液也是100克。80ML

回答3:

80的单位是mLi不是克
设原溶液质量为A,溶质质量为B,由方程
B/A=14%和B/A-100=28%知,B为28克
加热后溶液的物质的量浓度28g/56g/mol/80ml=0.5mol/80ml=6.25mol/L

回答4:

摩尔质量在数值上等于该种粒子的相对原子/分子/离子质量
相对原子质量的定义是以C12原子质量的1/12为“1”的。
一种离子的质量是C12原子1/12的多少倍,那么它的相对质量就是多少,摩尔质量的数值也是多少。
M=Mr这个是什么公式,没看懂
摩尔质量的定义是一摩尔某种物质的质量,一摩尔等于Na个该种离子,每个实际质量为m,则M=m*Na

回答5:

高一的学生

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