(2十4十6十8十……十98十100)一(1十3十5十7十…十97十99)的简便方法是什么?

2024-12-21 14:20:35
推荐回答(1个)
回答1:

原式=2+4+6+8+……+100-1-3-5-……-99
=(2-1)+(4-3)+(6-5)+()+(100-99)
=1+1+1+……+1
=1x50
=50

或者:原式=(2+100)x50÷2-(1+99)x50÷2
=102x50÷2-100x50÷2
=(102-100)x50÷2
=2x50÷2
=100÷2
=50