51问答网 > 现有100g溶质的质量分数为8%的硝酸钾溶液，若要使溶液中溶质的质量分数增大一倍，可采用的方法？

现有100g溶质的质量分数为8%的硝酸钾溶液，若要使溶液中溶质的质量分数增大一倍，可采用的方法？

2025-03-15 08:50:01
推荐回答（2个）
回答1：

1、加溶质
设加入硝酸钾的质量为X
（100g*8%+X)/(100g+X)*100%=2*8%
X=9.5g
所以A正确;B不正确;
2、蒸发溶剂
设蒸发水的质量为X
100g*8%/(100g-X)*100%=2*8%
X=50g

回答2：

1.加溶质;2.蒸发溶剂

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