(1)氯气和氢氧化钠反应生成NaCl、NaClO、水,反应为Cl2+2NaOH═NaCl+NaClO+H2O,
故答案为:Cl2+2NaOH═NaCl+NaClO+H2O;
(2)配制480mL 0.5mol?L-1 NaOH溶液,NaOH的质量为0.5L×0.5mol/L×40g/mol=10.0g,
故答案为:10.0;
(3)n(Cl2)=
=0.01mol,由Cl2+2NaOH═NaCl+NaClO+H2O可知,n(NaOH)=0.02mol,V=0.224L 22.4L/mol
=0.04L,故答案为:0.04.0.02mol 0.5mol/L