当51单片机振荡脉冲频率为6MHz是,分别计算节拍P,状态S,机械周期T?

2024-12-15 12:57:40
推荐回答(1个)
回答1:

节拍P(Phase) = 1/振荡频率 = (1/6) μs
状态S(State) = 2P = (1/3) μs
机器周期T(Machine Cycle) = 6S = 2 μs
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