已知x^2+xy=3,xy+y^2=-2,求下列各式的值 1. x^2-y^2 (2.) x^2+4xy+3y^2

已知x^2+xy=3,xy+y^2=-2,求下列各式的值 1. x^2-y^2 2. x^2+4xy+3y^2
2024-12-20 13:53:07
推荐回答(2个)
回答1:

1.
x^2-y^2=(x^2+xy)-(xy+y^2)
=3-(-2)
=5

2.
x^2+4xy+3y^2=(x^2+xy)+3(xy+y^2)
=3+3*(-2)
=-3

回答2:

x^2-y^2=(x^2+xy)—(xy+y^2)=3+2=5
x^2+4xy+3y^2=(x^2+xy)+3(xy+y^2)=3-6=-3