概率论一道,求解分布律,望有过程,必采

谢谢俶
2024-12-15 02:52:26
推荐回答(1个)
回答1:

(1)
P(X<5)=0
P(X=5)= 1/(10C5) = 1/252
P(X=6) = (5C4)/(10C5) = 5/252
P(X=7) = (6C4)/(10C5) = 15/252
P(X=8) = (7C4)/(10C5) = 35/252
P(X=9) = (8C4)/(10C5) = 70/252
P(X=10) = (9C4)/(10C5) = 126/252
P(X>10)=0
(2)
P(Y<1)=0
P(Y=1) = P(X=10) = 126/252
P(Y=2) = P(X=9) = 70/252
P(Y=3) = P(X=8) = 35/252
P(Y=4) = P(X=7) = 15/252
P(Y=5) = P(X=6) = 5/252
P(Y=6) = P(X=5) = 1/252
P(Y>6)=0