已知m^2-mn=21,mn-n^2=-12,求代数式m^2于n^2与m^2-2mn+n^2的值

2025-02-27 09:04:25
推荐回答(3个)
回答1:

m^2-mn=21 1
mn-n^2=-12 2

1+2得
m^2-mn+mn-n^2=m^2-n^=21-12=9

1-2得
m^2-mn-(mn-n^2)=m^2-2mn+n^2=21-(-12)=33

回答2:

m^2-n^2=21-12=9

m^2-2mn+n^2=21-(-12)=33

回答3:

m^2-n^2=21-12=9
m^2-2mn+n^2=21-(-12)=33