(1)50(x+1) 2 =72, 变形得:(x+1) 2 =
开方得:x+1=±
则x 1 =0.2,x 2 =-2.2; (2)3x 2 +8x-3=0, 变形得:x 2 +
配方得:x 2 +
开方得:x+
解得:x 1 =
(3)x 2 +3=2
变形得:x 2 -2
这里a=1,b=-2
∵△=b2-4ac=12-12=0, ∴x=
则x 1 =x 2 =
(4)2(x+3) 2 =x(x+3), 变形得:(x+3)[2(x+3)-x]=0,即(x+3)(x+6)=0, 可得x+3=0或x+6=0, 解得:x 1 =-3,x 2 =-6. |