解: x=1/(√2-1)=(√2+1)/((√2+1)(√2-1))=√2+1 根号X分之根号X-1乘(1+根号X分之一)的值 =(( √x-1)/√x)*(1+1/√x) =(( √x-1)/√x)*((√x +1)/√x) =( √x-1)(√x+1)/x =(x-1)/x (把x=√2+1带入)得: =(√2+1-1)/(√2+1) =√2/(√2+1) =(√2*(√2-1))/((√2+1)(√2-1)) =(2-√2)/1 =2-√2 亲,请您采纳,您的采纳是我的动力,谢谢。