由上面可以得出结论:x+x分之m=c+c分之m(m≠0)的解为:x1=c,x2=m/c
x+2/(x-1)=a+2/(a-1)
x-1+2/(x-1)=a-1+2/(a-1)
所以,x1-1=a-1得:x1=a
x2-1=2/(a-1),得:x2=2/(a-1)+1=(a+1)/(a-1)
所以,方程的根为:x1=a,x2=(a+1)/(a-1)
(1)x+m/x=c+m/c
∴x=c或x=m/c
(2)y+2/(y-1)=A+2/(A-1)
∴(y-1)+2/(y-1)=(A-1)+2/(A-1)
∴(y-1)²-[(A-1)+2/(A-1)]
(y-1)
+2=0
∴(y-1)²-[(A-1)+2/(A-1)]
(y-1)
+[(A-1)×2/(A-1)]
=0
∴[(y-1)
-(A-1)
][(y-1)
-2/(A-1)]
=0
∴Y1=A
Y2=1+2/(A-1)