用配方法解下列方程:x^2-2√3x+3=0 1⼀3x^2-1⼀2x+3⼀16=0 x^2+(√2+1)x+√2=0 (x+2)(x-2)= 2√2x

2024-12-20 03:06:35
推荐回答(1个)
回答1:

1. (x-√3)^2=0 x=√3

2. x^2-3/2x+9/16=0 得(x-3/4)^2=0 x=3/4

3. [x+(√2+1)/2]^2=[(√2-1)/2]^2
得x=-1或x=-√2

4. x^2- 2√2x-4=0
(x-√2)^2=6=(√6)^2
得x=√2±√6