(1)计算:sin420°?cos750°+sin(-330°)?cos(-660°)(2)求证:(cosβ-1)2+sin2β=2-2cos

2025-04-14 03:58:42
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回答1:

(1)sin420°?cos750°+sin(-330°)?cos(-660°)=sin60°cos30°+sin30°cos60°=sin(30°+60°)=sin90°=1.
(2)证明:(cosβ-1)2+sin2β=cos2β-2cosβ+1+sin2β=2-2cosβ.故原式成立.