1※(-2)
= 1×(-2) + 1 - (-2)
= -2 + 1 + 2
= 1
3*(-2)
= (-2)³
= -8
所以选C
1※(-2)=1*(-2)+1-(-2)=1
选C
3*(-2)=(-2)^3=-8
1※(-2)
解:原式=1×(-2)+1-(-2)
=-2+3
=1
3*(-2)
解:原式=(-2)³
= -8 所以选C
(1)1 (2)D