因式分解:x^4+3x^3-4x^2-8x+8

2024-11-25 03:45:00
推荐回答(2个)
回答1:

解:
x⁴+3x³-4x²-8x+8
=x⁴+x³-2x²+2x³+2x²-4x-4x²-4x+8
=x²(x²+x-2)+2x(x²+x-2)-4(x²+x-2)
=(x²+x-2)(x²+2x-4)
=(x-1)(x+2)(x²+2x+1-5)
=(x-1)(x+2)[(x+1)²-5]
=(x-1)(x+2)(x+1+√5)(x+1-√5)

回答2:

=x^2(x^2+3x-4)-8x+8
=x^2(x+4)(x-1)-8(x-1)
=(x-1)(x^3+4x^2-8)