解:x⁴+3x³-4x²-8x+8=x⁴+x³-2x²+2x³+2x²-4x-4x²-4x+8=x²(x²+x-2)+2x(x²+x-2)-4(x²+x-2)=(x²+x-2)(x²+2x-4)=(x-1)(x+2)(x²+2x+1-5)=(x-1)(x+2)[(x+1)²-5]=(x-1)(x+2)(x+1+√5)(x+1-√5)
=x^2(x^2+3x-4)-8x+8=x^2(x+4)(x-1)-8(x-1)=(x-1)(x^3+4x^2-8)