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51问答网 > 为什么碳酸根离子，硫酸根离子水解，溶液呈碱性

为什么碳酸根离子，硫酸根离子水解，溶液呈碱性

2025-03-14 22:55:16

推荐回答（3个）

回答1：

CO₃^2- + H2O = HCO3^- + OH-
so3^- + H2O = HSO3 + OH-
水解后把水的H结合，导致H减少，OH增多，显碱性

回答2：

最外层电子数不能大于8,次外层电子数除电子层数小于2层的原子外,其于原子均为8,因为a大于1,所以改原子的电子层数为2,若a等于2,则该原子为碳,质子数为6;若a等于3,则该原子为氧,质子数为8.该题选D.

回答3：

碳酸根水解显碱性！硫酸根却不然！

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