F(x)=sin(2x-π/3)
∵
ω=2
.∴T=2π/2=π
所以最小正周期是
π
又
2kπ-π/2＜2x-π/3＜2kπ+π/2
为增
2kπ-π/6＜2x＜2kπ+5π/6
kπ-π/12＜x＜kπ+5π/12
又
2kπ+π/2＜2x-π/3＜2kπ+3π/2
为减
2kπ+5π/6＜2x＜2kπ+11π/6
kπ+5π/12＜
x＜kπ+11π/12
所以，函数的增区间是
kπ-π/12＜x＜kπ+5π/12
减区间是
kπ+5π/12＜x＜kπ+11π/12
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