已知a是方程x2-3x+1=0的根,求代数式2a2-5a+2+3a2+1的值

2025-01-02 02:14:13
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回答1:

a是方程x²-3x+1=0的根
则,a²-3a+1=0
得,a²-3a=-1 ,a²+1=3a ,a+1/a=3

2a²-5a+2+3/a²+1
=2a²-6a+a+2+3/(3a)
=2(a²-3a)+a+2+1/a
=-2+a+2+1/a
=a+1/a
=3