(1)∵
=a sinA
=b sinB
,c sinC
∴sinC=
sinAsinC-sinCcosA,
3
∴
sinA-cosA=1,
3
∴2sin(A-
)=1,sin(A-π 6
)=π 6
,1 2
∴A-
=π 6
或π 6
π,5 6
∴A=
,A=π(舍),π 3
∴A=
π 3
(2)S△ABC=
bcsinA=1 2
3
?1 2
bc=
3
2
,
3
∴bc=4,
∵cosA=
b2+c2?a2