[(x^2 2xy-2x 2y-1)/(y^2-1)]*[(x^2-1)/(4y^2 xy-x y-1)]/[(y-1)/x-1)]是一个定值，则与x，y无关， [(x^2+2xy-2x+2y-1)/(y^2-1)]*[(x^2-1)/(4y^2+xy-x+y-1)]/[(y-1)/x-1)]= =[(0^2+2*0*0-2*0+2*)-1)/(0^2-1)]*[(0^2-1)/(40^2+0*0-0+0-1)]/[(0-1)/0-1)] =1*1=1
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