已知|a-1|+|b-2|=0,试求1⼀ab+1⼀(a+1)(b+1)+1⼀(a+2)(b+2)+......+1⼀(a+2009)(b+2009)的值

2024-12-19 13:54:08
推荐回答(1个)
回答1:

|a-1|+|b-2|=0
绝对值大于等于0,相加为0则都等于0
所以a-1=0,b-2=0
a=1,b=2

所以1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+......+1/(a+2009)(b+2009)
=1/1*2+1/2*3+1/3*4+......+1/2010*2011
=1-1/2+1/2-1/3+1/3-1/4+......+1/2010-1/2011
=1-1/2011
=2010/2011