求解题!!!急!!!

2024-12-28 22:35:56
推荐回答(1个)
回答1:

设两条对角线长为X1、X2,则
X1+X2=L,X1X2/2=S
边长^2=(X1/2)^2+(X2/2)^2=1/4(X1^2+X2^2)=1/4[(X1+X2)^2-2X1X2]
=1/4(L²-4S)
∴边长=1/2根号L²-4S
选 C