两边同时除以(X+1)的平方会得出（X—1）分之一等于四分之九结论X等于九分之十三
4(x+1)^2=9(x-1)^29(x-1)^2-4(x+1)^2=0[3(x-1)+2(x+1)][3(x-1)-2(x+1)]=0(5x-1)(x-5)=0x1=1/5，x2=5
[2（x+1）十3（x-1）][2（x+1）-3（x-1）]=0 x=1/5 x=5
