水果搭配的数学问题

2025-04-08 01:46:09
推荐回答(1个)
回答1:

某果品商店进行组合销售。甲种搭配:2千克A水果,4千克B水果:乙种搭配:3克A水果,8千克B水果,1千克C水果:丙种搭配:2千克A水果,6千克B水果,1千克C水果。已知A水果每千克2元,B水果每千克1.2元,C水果每千克10元。某天该商店销售这三种搭配共得441.2元,其中A水果的销售额为116元,问C种水果的销售额为多少元?
解:A水果卖出的数量:116÷2=58
千克
设甲种搭配卖出x份,乙种搭配卖出y份
那么丙种搭配卖出:(58-2x-3y)/2份
B水果销售额:[4x+8y+6×(58-2x-3y)/2]×1.2=208.8-2.4x-1.2y
C水果销售额:[y+(58-2x-3y)/2]×10=290-10x-5y
根据题意:208.8-2.4x-1.2y+290-10x-5y=441.2-116
12.4x+6.2y=173.6
2x+y=28
C水果的销售额:290-10x-5y=290-5×(2x+y)=150

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