y=ax^+bx+c怎么=a(x+b⼀2a)^+4ac-b^⼀4a

2025-03-10 05:39:14
推荐回答(1个)
回答1:

y=ax²+bx+c
=a(x²+bx/a+c/a)
=a(x²+bx/a+b²/4a²-b²/4a²+c/a)
=a[(x+b/2a)²+(4ac-b²)/4a²]
=a(x+b/2a)²+(4ac-b²)/4a