一道高数广义积分题

2025-02-26 05:28:30
推荐回答(1个)
回答1:

S∫a2(1-cost)2dt =a2∫(1-2cost+cos2t)dt =a2(t-2sint+∫cos2tdt) =a2[t-2sint+(1/2)∫(1+cos2t)dt] =a2[t-2sint+(1/2)t+(1/4)sin2t] =a2[(3/2)t-2sint+(1/4)sin2t]+C 当t=0→2兀时,上面的积分为 S=3a2兀