先化简,再求值:-x2-(3x-5y)+[4x2-(3x2-x-y)],其中x=12,y=?13

2025-01-01 09:08:58
推荐回答(1个)
回答1:

-x2-(3x-5y)+[4x2-(3x2-x-y)]
=-x2-3x+5+[4x2-3x2+x+y]
=-2x+6y,
x=

1
2
,y=?
1
3
时,原式=-3.