图
解如图。
无解
因左式的x^2-64y^2 = (x-8y)(x+8y),所以2x/(x^2-64y^2) = 2x/((x-8y)(x+8y)),所以1/(x-8y)=2x/(x^2-64y^2)-2x/((x-8y)(x+8y))=0,因x-8y为分母,所以x-8y不等于0,两边同乘以x-8y,得1=0(x-8y)=0,无解
