#include int main() { int n; int flag = -1; double sum = 0; printf(“请输入n=”); scanf("%d".&n); for(int i=0;i { flag *= -1; sum += flag/(n+1); } printf(“sum= %f”,sum); }
回答2：
#include
int main() { double a = 1-1.0/2+1.0/3-1.0/4+1.0/5-1.0/6; printf("%lf\n", a); return 0; }
