已知2sina+cosa⼀sina-3cosa=-5,求3cos2a+4sin2a的值 过程要完整 谢谢

2025-01-04 22:52:06
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回答1:

2sina+cosa=-5sina+15cosa
7sina=14cosa
sina=2cosa
sina²+cosa²=1
5cos²a=1
cos²a=1/5
3cos2a+4sin2a
=3(2cos²a-1)+8sinacosa
=6cos²a-3+16cos²a
=22cosa²-3
=22/5-3
=7/5